Acids = proton donors.
Weak acids - those that are not strong!
Weak acids do not ionize 100%.
Weak acids set up equilibrium with water to produce the acid's anion and hydronium ion.
If the general representation of a weak acid is HA, then in llbm:
HA(aq) + H2O <=> H3O+(aq) + A-(aq)
Generally two question types are asked
(1) Determine the Ka value for a particular weak acid
-given llbm information about [H3O+] via pH and/or %ionization information
-where pH can be used to determine [H3O+] @ llbm
-and where %ionization = [H3O+]llbm/[HA] x 100%
(2) Determine pH (or % ionization) given specific acid(useKa chart to determine Ka value)
Complete mathematical solution would include:
-llbm equation
-Ka expression
-ICE chart
-solve for whatever it is that is being asked
-looking for pH or %ionizn?
-solve for [H3O+]llbm, then calculate to get requested info
-looking for Ka, use pH or %ionzn to determine [H3O+]
Weak bases - similar set up as with weak acids
Difference, weak bases involve [OH-], which leads to pOH
If the geneal formula for a weak base is 'Base' and bases are proton acceptors
Generally: Base(aq) + H2O <=> BaseH+(aq) + OH-(aq)
Again given two basic question types
(1) Determine pH of a stated basic solution.
(2) Determine Kb of a stated base.
Complete mathematical solution would include:
-llbm equation
-Kb expression
-ICE chart
-solve for whatever it is that is being asked
-looking for pH?
-solve for [OH-]llbm , then determine pOH, then pH
@25C pH + pOH = 14.00
-looking for Kb use given pH (or pOH) to get to [OH-]llbm
Homework:
p568(8) p570(10) p574(12,13) p579(1,3,13)
Next up?
Using the Ka/Kb chart to calculate K values of conjugate ions
KaKb = Kw
Cute joke coming, ready? Why did the chicken cross the playground? [Ans: To get to the other slide.]