A few snackfood burning lab write-up tidbits:
-word processed - [use a decent sized font - please :<)]
-include a copy (real or reasonable reproduction) of the nutrition label
-follow along with the calculations as outlined on the assignment handout (hint, hint - using p320 #4(eicosane) as a guide for several aspects of the calculation - Did you read the posting from Day 3?)
-include the assignment sheet (its green) with the final submission
-joules to food calories (Cal as opposed to cal)
http://health.howstuffworks.com/health-illness/wellness/physical-fitness/weight-loss/calorie1.htm
Additional items to include
-include a cheesy joke in the footer (optional - but appreciated)
This colour of font was selected because of the cheesy nature of the following joke. Two antennas met on a roof, fell in love and got married. The ceremony wasn't much, but the reception was excellent. [In this age of digital/satellite cable, this joke is definitely from another era. If in doubt about its humour, share it with the parental figures. :<]
Thursday, October 8, 2009
Wednesday, October 7, 2009
Energy Day 3 - Representing Enthalpy Change
Four ways to represent enthalpy changes are to be considered.
-see the four ways outlined on page 319 of Nelson Chemistry 12
A nice review of thermochemical equations is found at"
http://chemistry.about.com/od/physicalchemistrythermo/a/thermochemlaws.htm
This next link has some questions with answers - available after you answer the question. The answer does not require units, but include a negative sign if required. One other tidbit for the questions, you need to ensure that you have calculated the molar enthalpy of the substance of interest. [That is, you may need to divide the stated enthalpy of the equation by the moles (coefficient) associated with the desired reactant.]
http://chemistry.csudh.edu/lechelpcs/thermoequationscsn7.html
From today: Page 319-320 [2,3,4,5] and page 320 [1 to 4]
A helpful hint for #4 page 320 (the eicosane question), the surroundings that are heated as a result of the burning candle are the copper container and the water in the copper container.
So - nH combustion eicosane = -[mcTwater + mcTcopper] ...once again, 'delta' represented by
One other thing with this question - in (d) a percentage error calculation is requested - consider the %difference calculation outlined on page 778 of Nelson Chemistry 12. [% difference/ % error - the calculation will work for both. In this case the predicted value = actual value = -13.3 MJ ...watch the units]
Now should you have to use a similar approach with a 'tin can' (~ iron) and a burning cheesie/chip/marshmallow/peanut/cracker......all the better. :<)
A few closing thoughts in honour of the potential cheesie burn - some cheesie jokes: (1) What do you call a fish with no eyes? A fsh (2) I went to buy some camouflage trousers the other day but I couldn't find any. (3) And finally, there was the person who sent twenty different puns to his friends, with the hope that at least ten of the puns would make them laugh. No pun in ten did.
-see the four ways outlined on page 319 of Nelson Chemistry 12
A nice review of thermochemical equations is found at"
http://chemistry.about.com/od/physicalchemistrythermo/a/thermochemlaws.htm
This next link has some questions with answers - available after you answer the question. The answer does not require units, but include a negative sign if required. One other tidbit for the questions, you need to ensure that you have calculated the molar enthalpy of the substance of interest. [That is, you may need to divide the stated enthalpy of the equation by the moles (coefficient) associated with the desired reactant.]
http://chemistry.csudh.edu/lechelpcs/thermoequationscsn7.html
From today: Page 319-320 [2,3,4,5] and page 320 [1 to 4]
A helpful hint for #4 page 320 (the eicosane question), the surroundings that are heated as a result of the burning candle are the copper container and the water in the copper container.
So - nH combustion eicosane = -[mcTwater + mcTcopper] ...once again, 'delta' represented by
One other thing with this question - in (d) a percentage error calculation is requested - consider the %difference calculation outlined on page 778 of Nelson Chemistry 12. [% difference/ % error - the calculation will work for both. In this case the predicted value = actual value = -13.3 MJ ...watch the units]
Now should you have to use a similar approach with a 'tin can' (~ iron) and a burning cheesie/chip/marshmallow/peanut/cracker......all the better. :<)
A few closing thoughts in honour of the potential cheesie burn - some cheesie jokes: (1) What do you call a fish with no eyes? A fsh (2) I went to buy some camouflage trousers the other day but I couldn't find any. (3) And finally, there was the person who sent twenty different puns to his friends, with the hope that at least ten of the puns would make them laugh. No pun in ten did.
Tuesday, October 6, 2009
Day 2 of Energy - Enthalpy & Molar Enthalpy
-once again, no 'delta' symbol appears - for now it is just a
(I haven't figured out the delta symbol part yet :<(
Two equations to consider
(1) H = nHx or (2) nHx = -mcT
where n - moles of system substance; Hx - molar enthlapy; H - enthalpy/ heat
If the question mentions the surroundings
- typically water (or a water-based solution, like a dilute acid or dilute base)
-surrounding information - amount of solution (volume, mass), temperature change info about surroundings
Then use the second equation [nHx = -mcT]
-when working with the mcT portion of the equation, make sure that mass (m) and the heat capacity (c) and the temperature change (T) are all for the same substance (the surroundings)
If the surroundings are not mentioned
-use the first equation
Other tidbits to consider
-the question may ask for or provide mass - convert to moles (n)
From today:
Do the following questions. Use proper form with your solutions.
Page 308 # 2 and Page 312 #1ab & 4** [H = nHx or nHx = -mcT]*
Page 310 – 4 & 5 and Page 312- 2, 3, 5
*where the H = 'delta'H
**don't let p312 #4 confuse you, the temperature mentioned is meant to mislead you, did it?
(I haven't figured out the delta symbol part yet :<(
Two equations to consider
(1) H = nHx or (2) nHx = -mcT
where n - moles of system substance; Hx - molar enthlapy; H - enthalpy/ heat
If the question mentions the surroundings
- typically water (or a water-based solution, like a dilute acid or dilute base)
-surrounding information - amount of solution (volume, mass), temperature change info about surroundings
Then use the second equation [nHx = -mcT]
-when working with the mcT portion of the equation, make sure that mass (m) and the heat capacity (c) and the temperature change (T) are all for the same substance (the surroundings)
If the surroundings are not mentioned
-use the first equation
Other tidbits to consider
-the question may ask for or provide mass - convert to moles (n)
From today:
Do the following questions. Use proper form with your solutions.
Page 308 # 2 and Page 312 #1ab & 4** [H = nHx or nHx = -mcT]*
Page 310 – 4 & 5 and Page 312- 2, 3, 5
*where the H = 'delta'H
**don't let p312 #4 confuse you, the temperature mentioned is meant to mislead you, did it?
Monday, October 5, 2009
Day 1 of Energy q=mct
- did a little bit of q = mc 'delta't
the mathematical calculations involve heat energy, but there is no acknowledge as to the origin of the energy - that will change - and soon
-terms, terms, terms.....
-system - the actual reaction
-surroundings - environment in which the reaction occured, typically water
-why water" (1) readily available (2) flows easily (3) high specific heat capacity - absorbs heat without experiencing a great temperature change (unlike some metals for example)
-when working with any dilute solution surroundings - assume that it has the same heat and density properties as pure water (c=4.18 J/gC, D = 1g/mL)
the mathematical calculations involve heat energy, but there is no acknowledge as to the origin of the energy - that will change - and soon
-terms, terms, terms.....
-system - the actual reaction
-surroundings - environment in which the reaction occured, typically water
-why water" (1) readily available (2) flows easily (3) high specific heat capacity - absorbs heat without experiencing a great temperature change (unlike some metals for example)
-when working with any dilute solution surroundings - assume that it has the same heat and density properties as pure water (c=4.18 J/gC, D = 1g/mL)
Energy Unit Ouline
• calculating enthalpy change q=mct
• molar enthalpy calculations – comparing system and surroundings
o nHx = H and nHx=-mct [Could not get the 'delta' symbol]
• 4 ways to represent enthalpy changes
A few methods to determine the energy change associated with a chemical reaction
• Method 1: Hess’s Law – add up some equations then add up the enthalpy change of each equation
• Method 2: Standard Enthalpies of Formation – using tabulated data
• Method 3: Bond energies – using still more tabulated data, this time: [bonds broken – bonds formed]
• Entropy – will a reaction tend to be spontaneous?
• Measuring Rates of Reactions – graphically and given experimental data & a balanced chemical equation
• factors Affecting Rates of Reactions
• Rate Laws
• Potential Energy Diagrams
• Collision Theory
• Mechanisms
• molar enthalpy calculations – comparing system and surroundings
o nHx = H and nHx=-mct [Could not get the 'delta' symbol]
• 4 ways to represent enthalpy changes
A few methods to determine the energy change associated with a chemical reaction
• Method 1: Hess’s Law – add up some equations then add up the enthalpy change of each equation
• Method 2: Standard Enthalpies of Formation – using tabulated data
• Method 3: Bond energies – using still more tabulated data, this time: [bonds broken – bonds formed]
• Entropy – will a reaction tend to be spontaneous?
• Measuring Rates of Reactions – graphically and given experimental data & a balanced chemical equation
• factors Affecting Rates of Reactions
• Rate Laws
• Potential Energy Diagrams
• Collision Theory
• Mechanisms
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